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2x^2/x+3=4.9
We move all terms to the left:
2x^2/x+3-(4.9)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
2x^2/x-1.9=0
We multiply all the terms by the denominator
2x^2-(1.9)*x=0
We multiply parentheses
2x^2-1.9x=0
a = 2; b = -1.9; c = 0;
Δ = b2-4ac
Δ = -1.92-4·2·0
Δ = 3.61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.9)-\sqrt{3.61}}{2*2}=\frac{1.9-\sqrt{3.61}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.9)+\sqrt{3.61}}{2*2}=\frac{1.9+\sqrt{3.61}}{4} $
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